Question about the (exactness of the) curvature form of a Hermitian metric

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From the local computation: $$\partial \bar{\partial} \log h =(\partial + \bar{\partial})\bar{\partial}\log h = d \bar{\partial} \log h,$$ it appears that the curvature form of a Hermitian metric is always exact, hence trivial in the De Rham cohomology class.

Could anyone tell me what's wrong with the computation?