Question in the definition of curvature

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$$K = \Bigg|\frac{dT}{ds}\Bigg| = \Bigg|\frac{\frac{dT}{dt}}{\frac{ds}{dt}}\Bigg|$$

where $T$ is the unit tangent vector to the curve and $s$ is arc lenght.

I don't know why that relationship is True in infinitesimals, in algebra I know the ratio $\frac{1}{dt}$ both in the numerator and the denominator is one but I am not sure how that works in infinitesimal and with an absolute value

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You have $s=s(t)$ and $T=T(s)=T(s(t))$.
Applying the chain rule you get $\frac{dT}{dt}=\frac{dT}{ds}\frac{ds}{dt}$ and then divide by $\frac{ds}{dt}$ to obtain your equality.