Question relating to the student test

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$S$ = sample standard deviation

I am not sure what the value for $\mu$ should be since we are trying to calculate $P({X}<1500)$, right? Any help will be greatly appreciated.

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$t = \frac{(\bar{X} - \mu)}{\frac{s}{\sqrt(n)}}$
with df = n-1

here
s = $1319.5852$
hence
$P(\mu- \bar{X} < 1500)$
$= P(\bar{X} - \mu > -1500)$
$=P(t > (\frac{-1500}{\frac{s}{\sqrt{n}}})$
$=P(t > \frac{-1500}{\frac{1319.585}{\sqrt{5}}}$
$= P(t > -2.5417)$
$= 0.9681$