Question: Why $(0,\infty) \subset \rho(\Delta_D) $ yields $\sigma(\Delta_D) \subset \mathbb R$?

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As I was studying the proof of the following theorem , I got stuck to the following implication:

$(0,\infty) \subset \rho(\Delta_D) \Rightarrow\sigma(\Delta_D) \subset \mathbb R (*)$

With the usual definition of spectrum I can see why:

$(0,\infty) \subset \rho(\Delta_D) \Rightarrow \sigma(\Delta_D) \subset \mathbb C \setminus (0,\infty)$

Hence, in order to deduce $(*)$ I should have used instead that: $\sigma(\Delta_D)=\mathbb R \setminus \rho(\Delta_D)$ but I don't get how this could be true here.

Any help is much appreciated!

Thanks in advance!