$R$ - commutative ring. $I$ - ideal of that ring. Prove that ring $R/I$ - is a field

69 Views Asked by At

$R$ - commutative ring. $I$ - ideal of that ring. Prove that ring $R/I$ - is a field and only if $I$ $!=$ $R$ and any proper ideal in $R$ does not contain $I$

1

There are 1 best solutions below

0
On

Let $R$ be a commutative ring and $k$ be a field. Assume $\phi\colon R\to k$ is a ring homomorphism and onto.

What can you conclude about $\ker\phi$ fomr the fact that $\phi$ is not the zero homomorphism?

What is the relation between ideals in $R$ containing $\ker\phi$ and ideals in $k$?