I have just begun studying this script about Random Walks, but I'm having trouble with a definition that is given there right at the beginning (page 10).
We're looking at Random Walks on the square lattice $\mathbb{Z}^d$ and the definition starts by establishing the notion of a generating set $V=\{x_1, \dots, x_m\}\subset \mathbb{Z}^d$ such that every $y \in \mathbb{Z}^d$ can be written as $y=a_1x_1+\dots+a_mx_m$ for sone $a_1, \dots, a_m \in \mathbb Z^d$. Next, we restrict ourselves to such generating sets $V$ such that for each $x \in V$ the first nonzero component of $x$ is positive. Given such a generating set $V=\{x_1, \dots, x_m\}$ and a function $\kappa: V \rightarrow (0,1]$ with $\kappa(x_1)+\dots+\kappa(x_m) \leq1$ an associated probability distribution $p$ on $\mathbb Z^d$ is defined as follows $$p(x_k)=p(-x_k)=\frac{1}{2}\kappa(x_k),\ p(0)=1-\sum_{x \in V} \kappa(x).$$
My problem: I don't see how $p$ is a well-defined probability distribution on $\mathbb Z^d$. I mean, for an arbitrary $y \in \mathbb Z^d$ we have $p(y)=p(a_1x_1+\dots+a_mx_m)$, but how do I come up with the probability of $y$? It's not like $p$ is a linear function or something, so I guess I'm missing some fundamental point of this definition...
Can anyone help me clarify this?
It is implied (and it should have been said) that all other probabilities are zero, i.e., the probability is supported by the origin, the basis vectors and their opposites; $p(y)=0$ unless $y$ is one of the $x_k$ or its opposite or the origin.
The interpretation is that a random walk has probability zero of taking two jumps (including diagonal jumps) at a time, and that it has equal probability of moving in either of two opposite directions.