Does someone have an idea how to work $\dfrac {3 \sqrt 2 - 4} {3 \sqrt 2 + 4}$ by rationalising the denominator method and simplifying?
2026-03-26 08:31:14.1774513874
Rationalise the denominator and simplify $\frac {3\sqrt 2-4}{3\sqrt2+4}$
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$\dfrac{3\sqrt 2 - 4}{3\sqrt 2 + 4} \cdot \dfrac{3\sqrt 2 - 4}{3\sqrt 2 - 4}=$
$=17-12\sqrt 2.$