The question is:
The reflection of the plane $2x+3y+4z-3=0$ in the plane $x-y+z-3=0$ is the plane:
I tried to find the equation of the normal to the plane and then tried putting in some values, but I couldn't do it. I know how to find the reflection of a point about a plane, but I have no idea how to proceed in this one.
Thanks.
Start with reflecting the normal of $2x+3y+4z-3=0$ in $x-y+z-3=0$ to get a new normal vector $(a,b,c)$. Write an equation $ax+by+cz+d=0$ for the new plane, and reflect a point of $2x+3y+4z-3=0$ in $x-y+z-3=0$ to get a point $(x,y,z)$. Insert this point into $ax+by+cz+d=0$ to find out $d$.