Regression Proof

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If the joint density function of $X$ and $Y$ is given by: $$f(x,y)= \begin{cases} 1/2, & \text{for } |x| + |y| \le 1 \\ 0, & \text{otherwise} \\ \end{cases}$$ Show that $Y$ has constant regression with respect to $X$ and/but that $X$ and $Y$ are not independant.

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Since $(X,Y)$ is uniform on the square with vertices $(\pm1,0)$ and $(0,\pm1)$, conditionally on $[X=x]$, $Y$ is uniform on its intersection with $\{x\}\times\mathbb R$, that is, uniform on the interval $(-1+|x|,1-|x|)$. In particular $\mathbb E(Y\mid X)=0$ while $(X,Y)$ is not independent.