When the residuals follow a normal distribution, the most likely function that fits the data is found using least squares. In that case:
$y = f(x_i) + r_i, \quad r\sim\mathcal{N}(0, \sigma^2)$
What happens when $r\sim\mathcal{N}(0, \sigma(x)^2)\:$?
When the residuals follow a normal distribution, the most likely function that fits the data is found using least squares. In that case:
$y = f(x_i) + r_i, \quad r\sim\mathcal{N}(0, \sigma^2)$
What happens when $r\sim\mathcal{N}(0, \sigma(x)^2)\:$?
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Then you have heteroscedasticity. The estimated values for the standard errors of the parameters are biased. And additional you can´t use the t-Distribution and the F-Distribution for testing the parameters.