I just started to learn matrix algebra. Using the properties has been straight forward but recently I've encountered a hiccup. That is, how do I represent a column vector with i rows and 1 column in the following equation?
$e^TA^{-1}(y+x) = c$
where A is a i by i matrix, x and y are column vector with i rows, c is a constant and e is column vector of 1's with i rows. I want to represent x in other terms.
I can get it to look like:
$e^TA^{-1}x = c - e^TA^{-1}y$
but I don't know how to deal with the $e^TA^{-1}$ term since we can't just divide it.
$x$ can't be uniquely determine.
Let $\color{blue}{x=Az}$, then we have
$$e^TA^{-1}(Az)=c-e^TA^{-1}y$$
$$\color{blue}{e^Tz=c-e^TA^{-1}y}$$
We just require the sum of components of $z$ to be equal to $c-e^TA^{-1}y$.
For example, a particular solution can be $x=A\left(\frac{c-e^TA^{-1}y}{i}e\right)=\left(\frac{c-e^TA^{-1}y}{i}\right)(Ae)$