Reverse fourier transformation of exponential

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What is the result to this formula: $$F^{-1}\left(\exp(\hat{f})\right)$$ with $F^{-1}$ the inverse fourier transformation? I tried to start with $$F^{-1} = \int\exp\left(\hat{f}(\omega)\right)\cdot\exp\left(2\cdot\pi\cdot i\cdot \omega\cdot x\right)d\omega\\ = \int \exp\left(\hat{f}(\omega)+2\cdot\pi\cdot i\cdot\omega\cdot x\right) d\omega $$ but now I am stuck. Is it possible to continue without knowing the fourier transformed function?