Rolling dice question

Question

I know that when 4 dice are rolled the probability of all 4 dice being 6's is .0008. How can I find the probability when all 3 dice are 6's when 3 dice are rolled?

Answer 1

There is a $1/6$ chance that rolling the first dice gives $6$. There is likewise a $1/6$ chance for the second and third dice. Since these are independent events, we can simply multiply to find that the probability is

$$\frac 1 6 \cdot \frac 1 6 \cdot \frac 1 6 = \frac 1 {216}$$