I'm trying to find the roots of this equation:
$(x^2-1)e^x=0$
I know that I could solve at first:
$(x^2-1)=0$ which has
$x=_{+-}1$
Here is the problem, because I sketched the graph also with Geogebra and the roots (of the entire equation) are only $-1$ and $1$, but if solve the equation:
$e^x=0$ with $ln(e^x)$ I know that the $x$ of $e$ is $0$.
So should the roots be $-1,0,1$? Why are they only $-1$ and $1$?
Thanks in advance!