Roots of polynomials of $R[x]$ in the surreals

Question

I have this question and I don't know where to even begin.

The question is: Let $S$ denote the surreals. Prove or disprove: no polynomial in $R[x]$ has a root in $S \setminus \mathbb{R}$.

Help!

Answer 1

Hint: All roots of polynomials in $\mathbb{R}[x]$ are (standard) complex numbers.