Roots of quadratic eqaution lies in an AP

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enter image description here I tried finding the common difference between the roots but didnt know what to do next. if someone could tell me how to solve this or give a headstart itll be a lot helpful

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HINT

The formulae for sum and product of roots gives $\frac{b^2-4ac}{a^2}=(\alpha - \beta)^2$. Compare this with the same result for the other quadratic and note that $\alpha-\beta=\gamma-\delta$.

NOTE

$(\alpha - \beta)^2=(\alpha + \beta)^2-4\alpha\beta =\frac{b^2}{a^2}-4\frac{ac}{a^2}$