Schrödinger Equation in Spherical Coordinates

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I am trying to learn how to solve three dimensional Schrödinger Equation in Spherical Coordinates. I was reading a text book and I found that there is a missed step in the solution, seen below:

The $\theta$ equation,$$\sin\theta\frac{\mathrm d}{\mathrm d\theta}\left(\sin\theta\frac{\mathrm d\Theta}{\mathrm d\theta}\right)+\left[\ell\left(\ell+1\right)\sin^2\theta-m^2\right]\Theta=0.\tag{4.25}$$is not so simple. The solution is $$\Theta(\theta)=AP_\ell^m\left(\cos\theta\right).\tag{4.26}$$where $P^m_\ell$ is the associated Legendre function, defined by $$P_\ell^m\left(x\right)\equiv\left(1-x^2\right)^{\vert m\vert/2}\left(\frac{\mathrm d}{\mathrm dx}\right)^{\vert m\vert}P_\ell(x).\tag{4.27}$$

It says that the solution of equation (4.25) is not simple and gives directly as equation (4.26). Can you help me to learn how to solve such differential equations?

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The $\theta$ equation,$$\sin\theta\frac{\mathrm d}{\mathrm d\theta}\left(\sin\theta\frac{\mathrm d\Theta}{\mathrm d\theta}\right)+\left[\ell\left(\ell+1\right)\sin^2\theta-m^2\right]\Theta=0.\tag{4.25}$$

You'll have to apply a variable change: let $x=\cos(\theta)$. That will lead you to the associated Legendre Differential Equation

\begin{equation} (1-x^{2})\frac{\mathrm{d}^{2}\Theta}{\mathrm{d}x^{2}}-\left(2x\frac{\mathrm{d}\Theta}{\mathrm{d}x}+\ell\left(\ell+1\right)-\frac{m^{2}}{1-x^{2}}\right)\Theta=0 \end{equation}

This is satisfied for values $x\in [-1,1]$ using Legendre Polynomials given by Rodrigues' formula:

\begin{equation} P_{\ell m}(x)=\frac{(-1)^{m}}{2^{\ell}\ell!}(1-x^{2})^{m/2}\frac{\mathrm{d}^{m+\ell}}{\mathrm{d}x^{m+\ell}}(x^{2}-1) \end{equation}

where $-\ell\leq m \leq \ell$

Here you can see a detailed solution.

I may recommend Arfken & Weber's Mathematical Methods for Physicists text.