Consider the series \begin{align} \sum_{n=1}^{\infty} \left[ \frac{n}{a} \ln\left(1 + \frac{a}{n}\right) - 1 + \frac{a}{2n} \right]. \end{align} Is there a closed form solution to this series and what is the value when $a=1, 2$ ?
2026-03-28 16:14:33.1774714473
Series involving a Logarithm
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For small $|a|$, $\ln(1 + a/n) = \sum_{j=1}^\infty (-1)^{j-1} (a/n)^j/j$, so your series is
$$ \sum_{n=1}^\infty \sum_{j=2}^\infty (-1)^{j} \dfrac{a^{j}}{(j+1)\; n^{j}} = \sum_{j=2}^\infty \dfrac{(-a)^{j}}{j+1} \zeta(j)$$
I don't think this has a closed form.