There is a known identity to evaluate a sum of the form
$$\sum_{n\geq1} \rho^n I_n(\omega) $$
Where $\rho>0$, $\omega >0$ and $I_n$ is the modified Bessel function of the first kind.
???
Thanks.
There is a known identity to evaluate a sum of the form
$$\sum_{n\geq1} \rho^n I_n(\omega) $$
Where $\rho>0$, $\omega >0$ and $I_n$ is the modified Bessel function of the first kind.
???
Thanks.
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$$ S = \sum_{n=1}^{\infty} x^nI_n(y) = \sum_{n=1}^{\infty} x^n \sum_{k = 0}^{\infty} \frac{\left(\frac{y}{2} \right)^{2k + n}}{k!\Gamma(n+k+1)}$$
$$ = \sum_{n=1}^{\infty} \left( \frac{xy}{2} \right)^n \sum_{k=0}^{\infty} \frac{\left( \frac{y^2}{4} \right)^k }{k!(n+k)!} = \sum_{n=1}^{\infty} \frac{\left( \frac{xy}{2} \right)^n}{n!} + \sum_{n=1}^{\infty} \sum_{k=1}^{\infty} \frac{\left( \frac{xy}{2} \right)^n \left( \frac{y^2}{4} \right)^k}{k!(n+k)!} $$
we can interchange
$$ = e^{\frac{xy}{2}} - 1 + \sum_{k=1}^{\infty} \frac{\left( \frac{y^2}{4} \right)^k}{k!} \sum_{n=1}^{\infty} \frac{\left(\frac{xy}{2} \right)^n}{(n+k)!} $$
$$ \sum_{n=1}^{\infty} \frac{\left(\frac{xy}{2} \right)^n}{(n+k)!} = \frac{\gamma \left(k,\frac{xy}{2} \right)}{\left(\frac{xy}{2} \right)^k (k-1)!e^{-\frac{xy}{2}}} - \frac{1}{k!}$$
$$ \Rightarrow S = e^{\frac{xy}{2}} - 1 + e^{\frac{xy}{2}}\sum_{k=1}^{\infty} \frac{k\gamma \left(k,\frac{xy}{2} \right)\left(\frac{y}{2x} \right)^k}{k!^2} - \sum_{k=1}^{\infty} \frac{\left(\frac{y^2}{4} \right)^k}{k!^2} $$
if this is right i think it became kinda easier
please edit if you saw anything wrong