I'm staring at
\begin{align*} \sum_{x=1}^\infty e^{ab^x} \frac{z^x}{x!} \end{align*}
I know that without the exponential, this series would be equivalent to $e^{z} - 1$. Together with the exponential, does it still permit a closed form?
I'm staring at
\begin{align*} \sum_{x=1}^\infty e^{ab^x} \frac{z^x}{x!} \end{align*}
I know that without the exponential, this series would be equivalent to $e^{z} - 1$. Together with the exponential, does it still permit a closed form?
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