Motivation:
I want to describe a rubber loop (see photo, the 3 violet parts are just decorative). Such a loop can be described as a torus but if you press the loop from the sides then its form resembles an ellipse, i.e. a deformed torus.
Equidistant points to a circle embedded in $\Bbb{R}^3$ form a torus. What is the name and equation of the shape formed by equidistant points to an ellipse embedded in $\Bbb{R}^3$? I could not find any source in the internet that deals with the description of such a shape.
In the literature we can find however an elliptic torus that is a different shape.
Edit:
A quite complicated parameterfree equation was given in an answer below. Is there another non-parametrized representation?


Topologically, your surface would still be considered a torus. (If it has a special name, I am not aware.)
In any event, you could use the Frenet-Serret equations to derive the following parametric equation:
$$\begin{align*} x&=a\cos u-\frac{b r \cos u\cos v}{\sqrt{b^2\cos^2 u+a^2\sin^2 u}}\\ y&=b\sin u-\frac{a r \sin u\cos v}{\sqrt{b^2\cos^2 u+a^2\sin^2 u}}\\ z&=r\sin v\end{align*}$$
where $a$ and $b$ are the ellipse's semiaxes, and $r$ is the radius of the circular cross-section. Here's a plot in Mathematica as an example:
One can use Gröbner bases to derive an implicit Cartesian equation, but the result is long and uninformative:
$$\small a^8 \left(b^4-2 b^2 \left(r^2+y^2-z^2\right)+\left(-r^2+y^2+z^2\right)^2\right)+a^4 \left(b^8+2 b^6 \left(r^2+3 x^2-2 y^2-z^2\right)-2 b^4 \left(3 r^4+r^2 \left(4 \left(x^2+y^2\right)-6 z^2\right)-3 x^4-4 z^2 \left(x^2+y^2\right)+5 x^2 y^2-3 y^4+3 z^4\right)+2 b^2 \left(r^6+r^4 \left(2 x^2-4 y^2-3 z^2\right)+r^2 \left(-3 x^4-4 z^2 \left(x^2-2 y^2\right)-3 x^2 y^2+5 y^4+3 z^4\right)+3 x^4 \left(z^2-y^2\right)+x^2 \left(y^2+z^2\right) \left(y^2+2 z^2\right)-\left(y^2+z^2\right)^2 \left(2 y^2+z^2\right)\right)+\left(-r^2+y^2+z^2\right)^2 \left(-r^2+x^2+y^2+z^2\right)^2\right)+b^4 \left(-r^2+x^2+z^2\right)^2 \left(b^4+2 b^2 \left(-r^2+x^2-y^2+z^2\right)+\left(-r^2+x^2+y^2+z^2\right)^2\right)=2 a^6 \left(b^6+b^4 \left(-r^2+2 x^2-3 y^2+z^2\right)-b^2 \left(r^4+r^2 \left(3 x^2+2 (y-z) (y+z)\right)+3 x^2 (y-z) (y+z)-3 y^4-2 y^2 z^2+z^4\right)+\left(-r^2+y^2+z^2\right)^2 \left(r^2+x^2-y^2-z^2\right)\right)+2 a^2 \left(b^8 \left(r^2+x^2-z^2\right)-b^6 \left(r^4-z^2 \left(2 \left(r^2+x^2\right)+3 y^2\right)+2 r^2 x^2+3 r^2 y^2-3 x^4+3 x^2 y^2+z^4\right)+b^4 \left(-r^6+r^4 \left(4 x^2-2 y^2+3 z^2\right)+r^2 \left(-5 x^4+x^2 \left(3 y^2-8 z^2\right)+3 y^4+4 y^2 z^2-3 z^4\right)+2 x^6-x^4 \left(y^2-5 z^2\right)+x^2 \left(3 y^4-3 y^2 z^2+4 z^4\right)-3 y^4 z^2-2 y^2 z^4+z^6\right)+b^2 \left(-r^2+x^2+y^2+z^2\right)^2 \left(r^4-r^2 \left(x^2+y^2+2 z^2\right)+z^2 \left(x^2+y^2\right)-x^2 y^2+z^4\right)\right)$$