Show that in any group of 9 people there is always a subgroup of 3 mutual strangers or a subgroup of 4 mutual acquaintances.
I know that this is an application of Ramsey's Theorem, but I'm not sure how to tackle the proof.
Show that in any group of 9 people there is always a subgroup of 3 mutual strangers or a subgroup of 4 mutual acquaintances.
I know that this is an application of Ramsey's Theorem, but I'm not sure how to tackle the proof.
As you noticed (and TorsionSquid pointed out) this exersice gives an upper bound for $\mathcal{R}(3,4)$. It happens to be the exact value of $\mathcal{R}(3,4)$. In order to see that, you have to demonstrate a red,blue-coloured $K_{8}$ without a red $K_{4}$ or a blue $K_{3}$.
Sketch of Solution:
The idea of the solution is to take a $K_{9}$ so that each person corresponds to a vertex, color the edge joining $A$ and $B$ red if $A$ and $B$ know each other, and blue if they do not and show that there will always be a red $K_{4}$ or a blue $K_{3}$.
Now, notice that there exists a vertex $V$ so that either (i) at least six of the edges adjacent to $V$ are red, or (ii) at least four of the edges adjacent to $V$ are blue.
In the first case donate $A$ the six-element set of their endpoints. (Does this reminds you something?) There is either a blue triangle, or red triangle on $A$ (why?) and we are done (why?).
In the second case donate $B$ the four-element set of their endpoints. If all edges on $B$ are red, then we are done. If there exists a blue edge on $B$ then this will form a blue triangle, together with $V$.