Show that one combination is more likely than others.

53 Views Asked by At

I have 2 variables shape X and size Y. Shape $X$ has 4 states ($x_{0}, x_1, x_2, x_3$) and size $Y$ has 3 states ($y_0, y_1, y_2$).

The contingency table could look like this:

Y \ X $x_0$ $x_1$ $x_2$ $x_3$
$y_0$ 350 50 40 0
$y_1$ 100 150 50 50
$y_2$ 10 90 10 5

How can I show that one combination ($x_0 / y_0$) is significantly likelier that the others? What is the correct "statistical" way to do that? Do I need the correlation coefficient for that?

Can I just say the probability that shape $x_0$ has size $y_0$ is $350/(350+50+40) = 0.795$ and that probability is higher than that for any other shape/size combination?