Suppose that $A$ and $B$ are any two events and $P(A)>0$, show that $$P(B\mid A^C)+P(B^C\mid A^C)=1$$
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2026-03-29 17:27:03.1774805223
Show that $P(B\mid A^C)+P(B^C\mid A^C)=1$
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Just use the definition for conditional probability of two events $$P(A|B) = \frac{P(A\cap B)}{P(B)}$$ And see where it takes you. Try drawing a Venn diagram.