Show that $T(JX,JY)+T(X,Y)=-\frac{1}{2}N_{J}(X,Y)$

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Let $(M,J,g)$ be a Riemannian manifold where $j$ is tensor field of type $(1,1)$ satisfying $J^2=1$. Then we have the following $$T(JX,JY)+T(X,Y)=-\frac{1}{2}N_{J}(X,Y),$$for all $X,Y \in\chi{M}$, where $T$ denotes the torsion tensor.

Could someone please help me prove this result? I am trying to prove by using the definition of Nijenhuis tensor as following $ N(JX,JY)=J^2[X,Y]+[JX,JY]-J[JX,Y]-J[X,JY]\\ = [X,Y]+[JX,JY]-J[JX,Y]-J[X,JY] $
$ T(X,Y)= \nabla_XY-\nabla_YX-[X,Y] .....(1)$\

and $T(JX,JY)=\nabla_{JX}JY-\nabla_{JY}JX-[JX,JY]....(2) $\ Ading (1) an (2) I coulnot get required result.So please help me how to proceed.

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Where did you found that relation? What you can prove (strongly relateded to almost complex structures on manifolds) is the following:

$\textbf{Claim}$: Let $(M,g,\nabla)$ be a Riemannian manifold endowded with a connection, and $J\in T^1_1(M)$ s.t. $J \circ J= -id_{T^1_1(M)}$ and $J$ compatible with the connection (i.e. $\nabla_X JY=J \nabla_X Y$), then
\begin{equation} N_J(X,Y)= T_{\nabla}(X,Y) + JT_{\nabla}(JX,Y) +JT_{\nabla}(X,JY) - T_{\nabla}(JX,JY) \end{equation} Proof. Expanding the RHS \begin{align*} RHS =&\nabla_X Y - \nabla_YX -[X,Y]+ J \nabla_{JX} Y - J\nabla_Y JX -J[JX,Y]+ \\&+J\nabla_{X} JY - J\nabla_{JY} X -J[X,JY]- \nabla_{JX} JY + \nabla_{JY} JX +[JX,JY]\\ =&\nabla_X Y - \nabla_YX -[X,Y]+ J \nabla_{JX} Y +\nabla_Y X -J[JX,Y]+ \\&-\nabla_{X} Y - J\nabla_{JY} X -J[X,JY]- J\nabla_{JX} Y + J\nabla_{JY} X +[JX,JY]\\ =&\ -[X,Y] -J[JX,Y] -J[X,JY] +[JX,JY]\\ =& J^2[X,Y] -J[JX,Y] -J[X,JY] +[JX,JY]=N_J(X,Y) \end{align*}

Not sure you can simplify the expression by some extra requirements to what you wrote down.