Show that the line with parametric equations don't intersect

Question

Show that the line with parametric equations $x = 6 + 8t$, $y = −5 + t$, $z = 2 + 3t$ does not intersect the plane with equation $2x − y − 5z − 2 = 0$.

To answer this do i just plug in the $x$, $y$, and $z$ equation into $2x − y − 5z − 2 = 0$? So $2(6 + 8t) − y − 5(−5 + t) − 2(2 + 3t) = 0 $

Answer 1

$2(6+8t)−(−5+t)−5(2+3t)−2=0$

$0t=5$

Therefore, there is no intersection.