Showing that $\Bbb R^2\backslash \{(0,0)\}$ is connected

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Using the definition

$\Omega\subset\Bbb R^n$ is connected iff it cannot be written as the union of two disjoint non empty opens $A$ and $B$ of $\Bbb R^n$,

how would you prove that $\Bbb R^2\backslash\{(0,0)\}$ ?

I know it is "path connected" by the standard definition of path connected, but in the definition that we use that does not imply connected.

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The definition you wrote does mean that path connected implies connected. That is, the statement

"If $X$ is path connected, then it is connected"

is true, if we use the definition of connectedness that you wrote.


However, if you want to prove $\mathbb R\setminus\{(0,0)\}$ is connected without resorting to the theorem above, you can still do it by sort of re-proving that theorem.

Assume that $X,Y$ are both closed, open and nonempty subsets of $\mathbb R\setminus\{(0,0)\}$. Then, as they are nonempty, there exists $x\in X, y\in Y$. Now, draw a path from $x$ and $y$, and prove that the path cannot be continuous and exist in $X$ and $Y$ at the same time.