How do I solve the following?
$$\dfrac{76!}{76!-75!}$$
$$76! = 76\cdot 75!$$
$$\frac{76!}{76!-75!} = \frac{75!\cdot 76}{75!(76-1)} = \frac{76}{75} $$
HINT
76! = 76*75! Plug that in and see what you get
Note that $76!=76*75!$ and that $76!-75!=75!(76-1)$, so then we see that $\frac{76!}{76!-75!}=\frac{76*75!}{75!(76-1)}=\frac{76}{75}$
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$$76! = 76\cdot 75!$$
$$\frac{76!}{76!-75!} = \frac{75!\cdot 76}{75!(76-1)} = \frac{76}{75} $$