Simplified is 0? $\log_{3} 9x^4 - log_{3}(3x)^2 $

Question

I have tried to solve this multiple ways, but I keep getting $2\log_{3}x$. According to the answer key, it is supposed to work out to 0, but I'm not seeing it. Can someone point me in the right direction?

$\log_{3} 9x^4 - log_{3}(3x)^2 $

Answer 1

Use two properties: $$ \log_{a}{bc} = \log_{a}{b}+ \log_{a}{c}$$ and $$ \log_{a}{(b^c)} = c\cdot\log_{a}{b}.$$

And it seems it is typo and your answer is right.