How can the expression AB'CD' + ABC'D' be simplified to AC'?
If context is needed, then this is the full expression:
A’B’C’D’ + A’B’C’D + A’BC’D + A’BCD + AB’C’D’ + AB’C’D + AB’CD’ + ABC’D’ + ABC’D + ABCD
And the simplified answer is:
BD + B'C' + AC'
I've gotten to BD + B'C' but I can't seem to simplify two stray terms down to AC'.
For the first part $\quad AB'CD' + ABC'D' = AD'\quad$ because both BB' and CC' are represented by $AD'.\quad$ I believe the entire eqpression simplifies as shown in the Veitch diagram below.