Simplify $\sqrt[3]\frac{-81y^7 z^2}{3yz^5}$

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"Simplify the radical expression completely. Use absolute value symbols if and only if needed. Rationalize all denominators and eliminate the negative exponents."

$\sqrt[3]\frac{-81y^7 z^2}{3yz^5}$

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$$\sqrt[3]{\frac{-81y^7z^2}{3yz^5}}=\sqrt[3]{\frac{-27y^6}{z^3}}=-\frac{3y^2}{z}$$