Simplifying $0.300 (1 \pm 0.0633)$

Question

This problem had to do with finding area with uncertainty, I got this far but I'm not sure how to go on. The answer to the next step is $(0.300 \pm 0.0190)$. How do they get this? What do we do with the 1? Thanks!

Answer 1

$0.300 * (1$ $^+_- 0.0633)$
$(0.300*1) + (0.300*$ $^+_- 0.0633)$
$0.300 $ $^+_- (0.300*0.0633)$
$0.300 $ $^+_- 0.0190$

Answer 2

recall the distributive property? $$a(b+c) = ab + ac$$ or in your case $$0.300(1±0.0633) = (0.300)(1)\pm (0.300)(0.0633)$$ $$\dots$$