I am unable to see how the following equation simplifies (approximately). Is a binomial approximation used, and if so how?
In the question we are told $\frac{1}{A} \ll 1$
$A^{2/3} -(A-4)^{2/3}\approx \frac{8}{3}\frac{1}{A^{1/3}}$
I am unable to see how the following equation simplifies (approximately). Is a binomial approximation used, and if so how?
In the question we are told $\frac{1}{A} \ll 1$
$A^{2/3} -(A-4)^{2/3}\approx \frac{8}{3}\frac{1}{A^{1/3}}$
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