Simplifying Radical Expression $\frac{\sqrt[3]{3a^4}}{\sqrt[3]{7b^2}}$

Question

$$\frac{\sqrt[3]{3a^4}}{\sqrt[3]{7b^2}}$$

I don't know how to simplify this. Everything I try to do just ends up with me taking out a single $a^3$. I tried a search on Wolfram Alpha but it didn't yield anything useful.

Answer 1

$$\frac{\sqrt[3]{3a^4}}{\sqrt[3]{7b^2}}= \left(\frac37\right)^\frac 13\left(\frac {a^2}b\right)^\frac23 =\left[\frac 37\left(\frac{a^2}b\right)^2\right]^\frac13$$ Different variations. Not necessarily simplified.