Simplifying this radical

Question

Sorry this is probably extremely easy but how do you simply the following radical? $$\sqrt[3]{(x+y)^4}$$

Is it just $(x+y)\sqrt[3]{x+y}$?

Answer 1

$$\sqrt[3]{(x+y)^4}$$ Break $(x+y)^4$ into terms $(x+y)^3(x+y)$ $$=\sqrt[3]{(x+y)^3(x+y)}$$ $$=\sqrt[3]{(x+y)^3}\cdot\sqrt[3]{(x+y)}$$ $$=(x+y)\sqrt[3]{(x+y)}\;\;\;\;\;\;\;\;\;\;\;\;\{\because \sqrt[3]{a^3}=a\}$$

Answer 2

$\sqrt[3]{(x+y)^4}$ $=>(x+y)^{4/3}$;
$(x+y)^{4/3}$ $=>(x+y)^{1+1/3}$ ;
$(x+y)^{1+1/3}$ $=>(x+y)^{1}.(x+y)^{1/3}$ ;
$(x+y)^{1}.(x+y)^{1/3}$ $=>(x+y).\sqrt[3]{(x+y)}$ ;