Slope of Tangent line of Polar Curve at Point

84 Views Asked by At

Question We had an examination today in college and the question was this:

Find the slope of the tangent line of polar curve $r = 3(1-\cos\theta)$ at point $B(\pi/3, 3/2 )$.

Answers are: $2\pi$, $\pi/3$, $1/2$, $\pi/2$ and 1.

I am no expert in math but nowhere have I ever seen some point in polar coordinate system as $r$ having a value with $\pi$ and $\theta$ with no $\pi$ at all. What kind of a point is $B$ like that. It was an online examination and I took a screenshot of the question so I didn't confuse the places of $r$ and $\theta$. I thought maybe they did and tried to solve the question accordingly, still couldn't find the answer. In other questions there were points given in the answers with $r$ having a value of $\pi$ * something and $\theta$ as a real value with no $\pi$.

Please clarify this I don't know what the problem is. Is there such a thing that they forgot to tell when teaching (that $r$ could be something with $\pi$) or they really made a huge mistake?