Question: . The solid obtained by revolving about the y-axis the region enclosed by the curves x = y^2 and x = y + 2
Where I get to:
What am I doing wrong? If for A(y) is change the order of radius subtraction I get a positive but I am sure that approach is incorrect.
Thanks
$y^2=y+2$ gives $y=-1$ or $y=2$.
Thus, the volume it's $$\pi\int\limits_{-1}^2((y+2)^2-(y^2)^2)dy=...$$ I got $14.4\pi.$