The physics exercises of today's lecture made me face following equation:
$$\cos(2x) - A\sin(2x) = 0$$
I was not able to solve for $x$? Do you know how to proceed?
(Note: A is $\approx -1/7$)
2026-04-13 08:57:11.1776070631
Solution of $\cos(2x) - A\sin(2x) = 0?$
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You can rearrange to get $$\tan(2x)=\frac{1}{A}\,.$$ The general solution is $$x=\frac{1}{2}\arctan\left(\frac{1}{A}\right)+\frac{n\pi}{2},$$ where $n$ is an integer.