Is the solution to the following:
$$a^2+b^2=1$$ $$c^2+d^2=1$$ $$ad+bc=1$$
still $a=d=\cos z$, $c=-b=\sin z$, when $a,b,c,d \in \mathbb C$?
Is the solution to the following:
$$a^2+b^2=1$$ $$c^2+d^2=1$$ $$ad+bc=1$$
still $a=d=\cos z$, $c=-b=\sin z$, when $a,b,c,d \in \mathbb C$?
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