I'm stuck here: $$\tan(y)=\frac{x·\sin(θ)-\sin(θ·x)}{x·\cos(θ)-\cos(θ·x)}$$
2026-04-09 15:28:15.1775748495
Solve for θ: $y = \arctan\Bigl(\frac{x· \sin(θ)- \sin(θ·x)}{x·\cos(θ)-\cos(θ·x)}\Bigr)$
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