Solve $K, L$ from 2 equations in terms of $p$.

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Denote $p=$ Price, $K=$ Number of robots, $L=$ Labour

$$\begin{cases}\dfrac{1}{3}pK^{-2/3}L^{1/3}= 2,\\ \\ \dfrac{1}{3}pK^{1/3}L^{-2/3}= 1.\end{cases}$$

Solve the above for $K$ and $L$.

The above two equations are the partial derivates of the product function:

$$f(K,L) = K^{1/3} L^{1/3}$$

It's a profit maximising exercise and I need to obtain the amount of inputs the firm hires. The answer is in the textbook but I just can't figure how they came up with it:

$$(K^{\ast},L^{\ast}) = (p^3/108 , p^3/54).$$

Thank you!

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Cube both equations, getting ones that are in $K^2L$ and $KL^2$. Divide them to get one in $\frac KL$ and multiply them and cube root to get one in $KL$. Multiply those to get one in $K^2$.