Four gallons of yellow paint plus two gallons of red paint make orange paint. I assume this makes six gallons. So the ratio is 4:2, or 2:1.
Question: how many gallons of yellow paint, and how many gallons or red paint, to make two gallons of orange paint?
2y + r = 2
2y + y = 2
3y = 2
y = 2/3
or
4y + 2r = 6
(4y + 2r)/3 = 2
so I get 4/3 and 2/3.
However, in this section of the text book, I'm not sure that it's "allowed" to do any of that. Is it possible to solve this just with cross-multiplying a ratio?
Their examples setup a ratio with an unknown n, cross multiply and solve for n. I don't see how to solve this word problem with that technique.
Hint
Take the problem in the other way.
You are told that $6$ gallons of orange paint are made mixing $4$ gallons of yellow paint and $2$ gallons of red paint.
Divide these numbers by 6 in order to come back to one gallon of orange paint. Then, one gallon of orange paint is made mixing $\frac{4}{6}=\frac{2}{3}$ gallons of yellow paint and $\frac{2}{6}=\frac{1}{3}$ gallons of red paint.
Now, multiply by $n$ which is the number of gallons of orange paint you want to make.
So, making $n$ gallons of orange paint require mixing $\frac{2n}{3}$ gallons of yellow paint and $\frac{n}{3}$ gallons of red paint.
Now, you want $n=2$; then ....
I am sure that you can take from here.