Solve $$8^ x +7\cdot 2^{x+1} = 7\cdot 4^x +8.$$
What's the best way to do this? Would I like convert to same indices?
Solve $$8^ x +7\cdot 2^{x+1} = 7\cdot 4^x +8.$$
What's the best way to do this? Would I like convert to same indices?
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Hint: I guess you mean $8^x+7 \cdot 2^x+1=7 \cdot 4^x +8$.
If so, put $y=2^x$. Then $y^3+7\cdot y +1 = 7y^2+8$.