Find all pairs of natural numbers $(m,n)$ such that:
$m!n! = m!+n!$
I just found the solution $(2,2)$
$$ (m!-1)(n!-1) = 1 $$ and both factors are nonnegative integers
Copyright © 2021 JogjaFile Inc.
$$ (m!-1)(n!-1) = 1 $$ and both factors are nonnegative integers