$$ \sqrt{14+ 8\sqrt{3}} = 2\sqrt{2} + b$$
Find b without using factoring
b=sqrt{6}
Other than saying that $b=\sqrt{14+8\sqrt{3}}-2\sqrt{2}$ is a perfectly correct answer, I will tell you that
$$ \sqrt{a+\sqrt{b}}=\sqrt{\frac{a+c}{2}}+\sqrt{\frac{a-c}{2}} $$ where $c^2=a^2-b$.
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Other than saying that $b=\sqrt{14+8\sqrt{3}}-2\sqrt{2}$ is a perfectly correct answer, I will tell you that
$$ \sqrt{a+\sqrt{b}}=\sqrt{\frac{a+c}{2}}+\sqrt{\frac{a-c}{2}} $$ where $c^2=a^2-b$.