Solve $U^TDZ^T = AU^TZ^T$ for $A$

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Let $U$ is an $m \times n$ matrix with rank $n (n < m)$. $D$ is a diagonal matrix of order $m$ and $Z$ is an $T \times m$ matrix mostly rank-deficient.

Can we solve the following equation for $A$:

$$U^TDZ^T = AU^TZ^T$$

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Your equation determines $A$ on the range of $U^T Z^T$. You can solve for $A$ if and only if that has dimension $n$.