Solving a factorial expression by factoring

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I'm trying to solve given factorial expression

$$\dfrac{(2n-1)!}{(3n-4)!} + \dfrac{(n+2)!}{(8-4n)!}$$

I noticed that there's $n!$ in common. Let me try to rewrite them.

$$\dfrac{n!\biggr [(2n-1)\cdot 1\biggr ]}{n!\biggr [(3n-4)(3n-3)(3n-2)(3n-1)\biggr ]}$$

However, I believe that my assumption is wrong so far.