If I have an ODE of the form:
$$
f'(g(t))=h(t),
$$
where $g$ is not necessarily invertible.
Is there a general solution for this type of ODE, if so when can I solve for f(t)?
2026-03-30 07:37:19.1774856239
Solving DDE of a composition
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This is not a well-posed question. Consider the simple case where $g(t) = t^2$ and $h(t) = t$. Set $t=1$, then the equation says $f'(1) = 1$. Now set $t = -1$, then the equation says $f'(1) = -1$. Clearly that does not make sense.