I am having some trouble solving the following question:
Find functions $g$ such that the following relation is true:
$x = g^{-1}(1/y)$.
Is there a general method to solve such inverse function equations?
Thanks.
I am having some trouble solving the following question:
Find functions $g$ such that the following relation is true:
$x = g^{-1}(1/y)$.
Is there a general method to solve such inverse function equations?
Thanks.
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If $g$ is a function of $x$ and $y$ then you cannot satisfy this equation because one could vary $y$ and thus change the right hand side while holding $x$ constant and thus keeping the left hand side constant. This is impossible. So I am going to assume that you make the following definition:
$$y\equiv g(x)$$
If this is not true, then rewrite your question.
The problem is then
$$x=g^{-1}\left(\frac{1}{g(x)}\right)$$
The way to solve this is to recognize that $g(g^{-1}(x))=x$ and thus, applying $g$ to both sides above, we have
$$g(x)=\frac{1}{g(x)}$$
or
$$g(x)^2=1$$
with solutions
$$g(x)=1,-1$$
so $g(x)$ is a constant function.
Edit: As is mentioned in the comments, the inverse of a constant function is not a function, so there are no solutions to this problem.