How can I solve $2^{6x}$ when $8^x=3$?
2026-04-08 22:00:41.1775685641
Solving pre logarithmic problems
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$2^{6x}=2^{3\cdot 2\cdot x}=2^{3\cdot x\cdot 2}=((2^3)^x)^2=(8^x)^2=3^2=9$